The dots are the individual deer each having one offspring on the first year and twins on the second. Except the first doe had twins on the first year. Too many variable obviously but using this table, there would be 17 deer year three.
I know our deer have twins and trips with little winterkill and no wolves yet. We have dumped 350 baldies over 10 years and still are treading water on herd reduction.
There's no answer to this because there are dozens if not hundreds of possible outcomes. If just one doe gives birth to 2 males or 2 females it would totally throw off the entire estimate if your guess was based on equal 1 male and 1 female outcome each time.
Does usually have more than one fawn as well but i want to know how many deer would there be if you start with one doe and she and her offspring have just one fawn a year for three years. .just doe fawns and no other factors Sent from my SCH-R530U using Tapatalk 4
Personally, I think the answer is one. One doe is all you'll have at the end of three years if the only surviving deer is a single doe. :D If I understand the OP correctly, he's using a hypothetical situation where you start with one doe and a few assumptions. Those assumptions are that each doe gets bred, has one fawn, it survives and it's a doe. In that case the answer is 8. You start with one and the number doubles each year. One doe started it all. At the end of year one there are two. At the end of year two there are four. At the end of year three there are eight.
I get 10 unique deer, I'm sure I'm wrong though Only counting the ones with x's next to them. Yr1 Original Doe X - Fawn1 X - Fawn1 Fawn X Yr2 Original Doe - Fawn2 X - Fawn2 Fawn X - Fawn1 - Fawn1 Fawn - Fawn1 Fawn Fawn X Yr3 Original Doe - Fawn3 X - Fawn3 Fawn X - Fawn2 - Fawn2 Fawn - Fawn2Fawn Fawn X - Fawn1 - Fawn1Fawn - Fawn1 Fawn Fawn - Fawn1 Fawn Fawn Fawn X 10 unique deer
Trick question. There had to have been a buck to breed the original doe unless this was all invitro hence they are all doe fawn and unique right?
I have not seen any one count the buck that must be breeding these does. Last time I checked does don't get pregnant by themselves. By all other assumptions the OP stated the answer would be 9 as he said.
I was assuming that the Buck was killed in late seaon in year 2 since the fawn birth stops in year three.
If the deer are bred in the 3rd year, then it would be 9. If you stop right at the 3rd year, it would be 6. Just depends on when you want to end it.
I can't believe people needed excel an calculators. First off the question is crazy as who knows what sex, if they survived winter, predators, or bred in first year. But if we're in lala land and every year they had a doe fawn which would be pregnant next year and no one bothered them. The doe would have 1 fawn. Year two doe would have a second fawn while last years will have one. Year three for has another, and previous two have one. Total 1 original doe and 6 new does.
