It is much more difficult than that, Score, B.C. (t) = ⌠40yds ⌠15 mph NNE⌠6 harmonic dampeners ...| ........ |...................|. .........( {[1+cos^2(treestand angle)]^3 )^3 ...|..........|...................| .........( -----------------------------------------) dBucks dDoes dHalloween ...| .........| ..................| ..........([Heartland^-1(soybeans/brassicas)]) ...⌡0 yds .⌡5mph NE ....⌡ 3 harmonic dampeners Where: .............δbuck*δHerd dBuck = ------------------ .............δHerd*δAcres ...............dCoyotes dDoes = ------------------ ................dAcorns ......................δtemperature*δLonewolf Alpha II dHalloween = ------------------------------------------ ......................δDaytime Stealth Cam*δFace paint Thus, Obviously, B.C. (t) = Fergie Clause * Limit (B.C.^-1(t)) ........................................Arrows shot ->3
consider this: IF: Spot N Stalk=poacher And DON WEDDLE met Fred Bear in 83' with the variable of Tony being banned, At what point does poacher intersect paths with Tony using the given formula of V=d/t?? simplify your answer
Since, we all know tony was brought back from banishment, one must use the theory of relativity to explain why a preacher and a poacher would share a memory from '83.