I shoot "the drive" model PSE compound bow. My arrow and draw length are 26.5 inches. I use 100 grain target tips and goldtip 400 arrows. It is set at 50 lbs. Assuming there is no wind and I am on flat ground, how far will my arrow go if shot at the optimal angle(44.5 degrees?) Thanks! -Joe
If you get a exact fps of your bow with your arrows, and arrow weight with tips on. That is easy to find out. The type of bow, draw length and weight arnt needed in that equation
I'm not that good at physics. But I could tell you how far it would go in a vaccume. Or if you crono your arrows right off the bow and at 20 yards. I could get it.
You have not provided the needed data to calculate the answer you seek. What is your total projectile weight and projectile speed?
I need to your arrow velocity, but I will guess and take a stab at this. If your arrow velocity is 250 ft/s (converts to 76.2 m/s), then its (x,y) coordinates are found: Y = V sin 44.5 *t - 0.5*g*t^2 where g is gravity constant and equals -9.8 m/s/s that is why I had to convert fps to m/s. X = V cos 44.5 *t To try and keep it less cluttered I purposely left off the units until the end. We need to know how long it is in the air. We'll call this time T. So Y =0 because the change in Y (delta Y) is essentially zero because it starts and lands "close enough" to same height. 0 = V sin 44.5 *T - 0.5 *g *T^2 T = 2 * V * sin 44.5/g = 2*250* sin 44.5/9.8 = 10.9 s So now we need to find the change in X (delta X = distance traveled). DeltaX = [v(initial) + v(final)]t/2 = [76.2cos44.5 + 76.2cos44.5]10.9s/2 = 592.4 m
Ha! As with most of mathematics, physics, engineering, etc., you just have to make sense of the problem, then go find the equations you need. As an electrical engineer I don't do much of this kind of stuff, but I find it fun actually. I'm a geek though .
Ahh physics :/ I'm glad I chose electrical and not mechanical. We only need to know 3 equations Sent from my iPhone using Tapatalk
Forget all that math crap LOL, I know an easier way to do this. Find a huge field and launch that sucker. Then measure the distance.
I weighed 3 of my arrows. The weights were as follows; 23.1 grams = 356.487478 grain 23.2 grams = 358.030714 grain 23.3 grams = 359.57395 grain Let's assume that barometric pressure is between 25-35 inHg, humidity is between 40-75%, 0 wind, flat ground with no obstructions, and the temperature being between 50-80F. I believe the drive maxes out at 340fps.(iirc, feel free to correct me) From what I've read it loses 10fps for every inch taken off the draw length. Since I'm shooting at 26.5 inches that means it's getting knocked down 35fps. I'm also reading for every 10 lbs. of reduction in draw weight, expect to lose around 15-20 FPS. So since I'm shooting it with a 50lb draw (it maxes out at 70) I'm losing between 30-40fps. I am also reading that a peep and d-loop add another 15 grain to my string which takes away approximately 5-6fps. Then there's this; "IBO tests are conducted using an automated shooting machine that releases the string with absolute perfection. A human isn’t capable of such release accuracy as a machine. For this reason, you’ll need to subtract another 2-3 FPS compared to the IBO rating." Also this; "For every extra 5 grain of arrow weight over 350, expect the speed of your bow to be reduced by around 1.5 FPS." So I'm losing between 1.5-3fps on top of everything else. I estimate my bow is shooting at approximately 260fps. I feel as though your calculation of 197.3 yards is not *too* far off. Could you calculate how far it would travel with the extra 10fps since you based your calculations off of the assumption that it'd be shooting at 250fps? I imagine it'd be closer to 205.56 yards. (I'm not good at math) Unfortunately I don't have any place where I can shoot 200+ yards. So that's out of the question.
I came up with 592m so I think I was close. What's wrong with wanting to know? Knowledge is not a bad thing.
